", "upvoteCount": 0, "url": "https://trailhead.salesforce.com/trailblazer-community/feed/0D54V00007T4LA6SAN", "datePublished": "2018-12-13T15:37:47.000Z", "author": { "@type": "Person", "name": "Tyler Brooks", "url": "https://trailblazers.salesforce.com/profileView?u=0053A00000DptxEQAR", "affiliation": { "@type": "Organization", "name": "American Innovations" } } } ] } }
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Topics#VisualforceTyler Brooks's Question
Tyler Brooks (American Innovations) asked in #Visualforce
Dec 12, 2018, 3:12 PM

How to get submit button to be enabled after checkbox is checked on page?

I have some code for a page and I have it to where the submit button is greyed out if a checkbox is unchecked. However whenever you check the box it doesn't enable the submit button like i'm wanting. 

Here is my code 

<apex:page standardController="RMA__c">
    <apex:form >
        <apex:outputPanel id="thePanel" rendered="{!(RMA__c.RLI_has_QUOTE_SO__c == true)}">
        <apex:pageBlock title="Confirm Information" mode="edit">
            <apex:pageBlockSection title="Confirm the  new field values" columns="2" rendered="{!(RMA__c.Show_the_box__c == true)}">
                <apex:outputfield value="{!RMA__c.Contact__c}"/>
                <apex:outputfield value="{!RMA__c.Shipping_Priority__c}"/>
                <apex:outputfield value="{!RMA__c.Ship_to_Address__c}"/>
                <apex:outputfield value="{!RMA__c.Bill_to_Address__c}"/>
                <apex:inputfield value="{!RMA__c.Request_Priority__c}"/>
                <apex:inputField value="{!RMA__c.Changes_are_reviewed__c}"/>
            </apex:pageBlockSection>
            <apex:pageBlockButtons >
                <apex:commandButton action="{!save}" value="Submit" disabled="false" rendered="{!(RMA__c.Changes_are_reviewed__c == true)}"/>
                <apex:commandButton action="{!save}" value="Submit" disabled="true" rendered="{!(RMA__c.Changes_are_reviewed__c != true)}"/>
            </apex:pageBlockButtons>
        </apex:pageBlock>
        </apex:outputPanel>
    </apex:form>
</apex:page>

And here is the page:

How to get submit button to be enabled after checkbox is checked on page?​​​​​​​
5 answers
  1. Tyler Brooks (American Innovations)
    Dec 14, 2018, 3:37 PM
    So I figured out the answer to my question and the reason it wasn't working before, for others who are having this issue here is my code:

     

    <apex:page standardController="RMA__c">
        <apex:form >
            <apex:outputPanel id="thePanel" rendered="{!(RMA__c.RLI_has_QUOTE_SO__c == true)}">
            <apex:pageBlock id="TheBlock" title="Confirm Information" mode="edit">
                <apex:pageBlockSection id="theSection" title="Confirm the  new field values" columns="2" rendered="{!(RMA__c.Show_the_box__c == true)}">
                    <apex:outputfield value="{!RMA__c.Contact__c}"/>
                    <apex:inputfield value="{!RMA__c.Shipping_Method__c}"/>
                    <apex:outputfield value="{!RMA__c.Ship_to_Address__c}"/>
                    <apex:outputfield value="{!RMA__c.Bill_to_Address__c}"/>
                    <apex:inputfield value="{!RMA__c.Request_Priority__c}"/>
                    <apex:inputfield value="{!RMA__c.Specific_Asset_Requested__c}"/>
                    <apex:inputField value="{!RMA__c.Changes_are_reviewed__c}" id="reviewed">
                        <apex:actionSupport event="onchange" rerender="thePanel"/> 
                    </apex:inputField>
                </apex:pageBlockSection>
                <apex:pageblockButtons id="button">
                <apex:commandButton value="Submit" action="{!save}" id="saveit" disabled="{!IF(RMA__c.Changes_are_reviewed__c!=true,true,false)}"/>
                </apex:pageblockButtons>
           </apex:pageBlock>
            </apex:outputPanel>
        </apex:form>
    </apex:page>

    The reason it wasn't work was because I was adding the onchange to the same line as the input field value for the checkbox, not doing the action Support in a seperate line like shown in my correct code.

    Hope this helps others!

    -Tyler
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